Which of the following set of horizontal forces would lead an object in equilibrium? (a) 5N 10N 20N (b) 6N 12N 18N (c) 8N 8N 8N (b) 2N 4N 8N 16N


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Question Number 107905 by aurpeyz last updated on 13/Aug/20

$W h i c h o f t h e f o l l o w i n g s e t o f h o r i z o n t a l$ $f o r c e s w o u l d l e a d a n o b j e c t i n e q u i l i b r i u m ?$ $(a) 5 N 10 N 20 N$ $(b) 6 N 12 N 18 N$ $(c) 8 N 8 N 8 N$ $(b) 2 N 4 N 8 N 16 N$
Commented by aurpeyz last updated on 13/Aug/20

$p l s h e l p m e w i t h s o l u t i o n a n d e x p l a n a t i o n$
Commented by mr W last updated on 13/Aug/20

Commented by mr W last updated on 13/Aug/20

$o n l y i f a l l f o r c e s c a n f o r m a c l o s e d$ $s h a p e .$ $(b), (c) a r e p o s s i b l e$
	Answered by Don08q last updated on 13/Aug/20

	$The object will be in equilibrium if$ $and only if one (t h e r e s u l t a n t) of the$ $forces in any of the sets is equal to the$ $algebraic sum of the others . In this$ $case, that force must be directed to$ $oppose the continuous directions of the$ $other forces .$ $(b) 6 N + 12 N = 18 N$ $(d) 2 N + 4 N + 8 N = 16 N$
	Commented by mr W last updated on 13/Aug/20

	$n o t c o r r e c t s i r! w h a t y o u s a i d i s o n l y$ $v a l i d i f a l l f o r c e s a r e i n t h e s a m e$ $d i r e c t i o n .$ $g e n e r a l l y i n 2 D o r i n 3 D,$ $t h e c o n d i t i o n i s Σ \vec{F_{i}} = 0, t h a t m e a n s$ $a l l f o r c e s s h o u l d b e a b l e t o f o r m a$ $c l o s e d p o l y g o n .$ $b e s i d e s 2 + 4 + 8 = 14 \neq 16!$
	Commented by mr W last updated on 13/Aug/20

	Commented by mr W last updated on 13/Aug/20

	$t h e s e t h r e e f o r c e s a r e i n e q u i l i b r i u m .$
	Commented by Don08q last updated on 13/Aug/20

	$Y e s . T h a n k s f o r t h e c o r r e c t i o n$
	Commented by aurpeyz last updated on 15/Aug/20

	$t h a n k s f o r t h e a n s w e r s$
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