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Question Number 107976 by anonymous last updated on 13/Aug/20

Rewrite cos6xcos 4x as a sum or  difference

$${Rewrite}\:\mathrm{cos6}{x}\mathrm{cos}\:\mathrm{4}{x}\:{as}\:{a}\:{sum}\:{or} \\ $$$${difference} \\ $$

Answered by mathmax by abdo last updated on 13/Aug/20

cos(4x)cos(6x) =(1/2){cos(10x) +cos(2x)}

$$\mathrm{cos}\left(\mathrm{4x}\right)\mathrm{cos}\left(\mathrm{6x}\right)\:=\frac{\mathrm{1}}{\mathrm{2}}\left\{\mathrm{cos}\left(\mathrm{10x}\right)\:+\mathrm{cos}\left(\mathrm{2x}\right)\right\} \\ $$

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