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Question Number 108082 by ismoilov last updated on 14/Aug/20

Answered by Her_Majesty last updated on 14/Aug/20

$$x={tan}^{-1}t$$$$\frac{(t+1)(t-2)}{t^2+1}⩾0\Rightarrow -1⩽t⩽2$$$$\Rightarrow for0⩽x<2\pi$$$$\frac{\pi }{2}-{tan}^{-1}\frac{1}{2}⩽x⩽\frac{3\pi }{4}\vee \frac{3\pi }{2}-{tan}^{-1}\frac{1}{2}⩽x⩽\frac{7\pi }{4}$$

Commented by Jamshidbek2311 last updated on 14/Aug/20

$$thankyou$$

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