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Question Number 108107 by otchereabdullai@gmail.com last updated on 14/Aug/20

Commented by rexfordattacudjoe last updated on 16/Aug/20

By similarities,(r/(24))=((10)/(20))  r=((10×24)/(20))  r=12cm

Bysimilarities,r24=1020r=10×2420r=12cm

Commented by rexfordattacudjoe last updated on 16/Aug/20

length of an arc=(θ/(360))×2Πr  20=(θ/(360))×2(((22)/7))(24)  50400=1056θ  θ=47.7°

lengthofanarc=θ360×2Πr20=θ360×2(227)(24)50400=1056θθ=47.7°

Answered by JDamian last updated on 14/Aug/20

(a)  20 = 24 ∙ θ  ⇒ θ = (5/6) rad  10 = r ∙ θ  ⇒ r = ((10)/θ) = ((10)/(5/6)) = 12 cm.  (b)   20 + 10 + 2∙(24−12) = 54 cm.    (c)  from (a):  θ = (5/6) rad =  = (5/6) × ((180)/π) = ((150)/π) ≈ 47.75°

(a)20=24θθ=56rad10=rθr=10θ=1056=12cm.(b)20+10+2(2412)=54cm.(c)from(a):θ=56rad==56×180π=150π47.75°

Commented by otchereabdullai@gmail.com last updated on 15/Aug/20

thank you sir

thankyousir

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