y=e^x ln(sin2x) (dy/dx)=??


Question and Answers Forum

All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 108238 by Study last updated on 15/Aug/20

$y = e^{x} l n (s i n 2 x) \frac{d y}{d x} = ? ?$
	Answered by Dwaipayan Shikari last updated on 15/Aug/20

	$\frac{d y}{d x} = e^{x} l o g (s i n 2 x) + 2 e^{x} \frac{c o s 2 x}{s i n 2 x}$ $\frac{d y}{d x} = e^{x} (l o g (s i n 2 x) + 2 c o t 2 x)$
	Answered by john santu last updated on 15/Aug/20

	$\frac{♡ J S ♡}{}$ $\frac{d y}{d x} = e^{x} \ln (\sin 2 x) + e^{x} (\frac{2 \cos 2 x}{\sin 2 x})$ $= e^{x} [\ln (\sin 2 x) + 2 \cot 2 x]$
	Answered by mathdave last updated on 15/Aug/20

	$s o l u t i o n$ $\frac{d y}{d x} = e^{x} ∙ 2 \frac{\cos 2 x}{\sin 2 x} + e^{x} \ln (\sin 2 x)$ $\frac{d y}{d x} - y = 2 e^{x} \cot 2 x$
	Answered by mathmax by abdo last updated on 15/Aug/20
	$y(x) =e^x ln(sin(2x)) ⇒(dy/dx) =e^x ln(sin(2x))+e^x .((2cos(2x))/(sin(2x))) =e^x {ln(sin(2x)) +(2/(tanx))}$
	$y (x) = e^{x} \ln (\sin (2 x)) \Rightarrow \frac{dy}{dx} = e^{x} \ln (\sin (2 x)) + e^{x} . \frac{2 \cos (2 x)}{\sin (2 x)}$ $= e^{x} {\ln (\sin (2 x)) + \frac{2}{tanx}}$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum