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Question Number 108326 by abony1303 last updated on 16/Aug/20

Commented by abony1303 last updated on 16/Aug/20

$$\mathrm{pls}\mathrm{help}$$

Answered by mr W last updated on 16/Aug/20

$$a=pq$$$$b>a\Rightarrow b>pq$$$$$$$$a^2=p^2{q}^2=nb$$$$\Rightarrow b=p^{2}q,n=q$$$$\Rightarrow b={pq}^2,n=p$$

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