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Question Number 108406 by pticantor last updated on 16/Aug/20
solvethedifferentialequationy′−2exy=2exy
Answered by Dwaipayan Shikari last updated on 16/Aug/20
dydx=2ex(y+y)∫dyy+y=∫2exdx∫dyy(1+y)dy=2ex+C∫2tt(1+t)dt=2ex+Cy=t2,1=2tdtdy2log(1+t)=2ex+Clog(1+t)=ex+C2log(1+y)=ex+C2
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