Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 108430 by Rasikh last updated on 16/Aug/20

Answered by Sarah85 last updated on 17/Aug/20

42! has got more 2s than 3s, so we have to  count the 3s  3, 6, 12, 15, 21, 24, 30, 33, 39, 42 / 10 3s  9, 18, 36 / 6 3s  27 / 3 3s  ⇒ n=19

$$\mathrm{42}!\:\mathrm{has}\:\mathrm{got}\:\mathrm{more}\:\mathrm{2s}\:\mathrm{than}\:\mathrm{3s},\:\mathrm{so}\:\mathrm{we}\:\mathrm{have}\:\mathrm{to} \\ $$$$\mathrm{count}\:\mathrm{the}\:\mathrm{3s} \\ $$$$\mathrm{3},\:\mathrm{6},\:\mathrm{12},\:\mathrm{15},\:\mathrm{21},\:\mathrm{24},\:\mathrm{30},\:\mathrm{33},\:\mathrm{39},\:\mathrm{42}\:/\:\mathrm{10}\:\mathrm{3s} \\ $$$$\mathrm{9},\:\mathrm{18},\:\mathrm{36}\:/\:\mathrm{6}\:\mathrm{3s} \\ $$$$\mathrm{27}\:/\:\mathrm{3}\:\mathrm{3s} \\ $$$$\Rightarrow\:{n}=\mathrm{19} \\ $$

Commented by Rasikh last updated on 17/Aug/20

thans a lot sir

$$\mathrm{thans}\:\mathrm{a}\:\mathrm{lot}\:\mathrm{sir} \\ $$

Commented by udaythool last updated on 17/Aug/20

There are 14 no.s which are  multiple of 3, 4 multiple of 9 and  1 multiple of 27.  Therefore 42! is a multiple of 3^(14+4+1) =3^(19) .  No doubt 42! is a multiple of  more than 19th power of 2. Thus  42! is a multiple of  19th power of 6, since 2 and 3  are relatively prime.

$$\mathrm{There}\:\mathrm{are}\:\mathrm{14}\:\mathrm{no}.\mathrm{s}\:\mathrm{which}\:\mathrm{are} \\ $$$$\mathrm{multiple}\:\mathrm{of}\:\mathrm{3},\:\mathrm{4}\:\mathrm{multiple}\:\mathrm{of}\:\mathrm{9}\:\mathrm{and} \\ $$$$\mathrm{1}\:\mathrm{multiple}\:\mathrm{of}\:\mathrm{27}. \\ $$$$\mathrm{Therefore}\:\mathrm{42}!\:\mathrm{is}\:\mathrm{a}\:\mathrm{multiple}\:\mathrm{of}\:\mathrm{3}^{\mathrm{14}+\mathrm{4}+\mathrm{1}} =\mathrm{3}^{\mathrm{19}} . \\ $$$$\mathrm{No}\:\mathrm{doubt}\:\mathrm{42}!\:\mathrm{is}\:\mathrm{a}\:\mathrm{multiple}\:\mathrm{of} \\ $$$$\mathrm{more}\:\mathrm{than}\:\mathrm{19th}\:\mathrm{power}\:\mathrm{of}\:\mathrm{2}.\:\mathrm{Thus} \\ $$$$\mathrm{42}!\:\mathrm{is}\:\mathrm{a}\:\mathrm{multiple}\:\mathrm{of} \\ $$$$\mathrm{19th}\:\mathrm{power}\:\mathrm{of}\:\mathrm{6},\:\mathrm{since}\:\mathrm{2}\:\mathrm{and}\:\mathrm{3} \\ $$$$\mathrm{are}\:\mathrm{relatively}\:\mathrm{prime}. \\ $$

Commented by Rasikh last updated on 18/Aug/20

thank you

$$\mathrm{thank}\:\mathrm{you} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com