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Question Number 10853 by geovane10math last updated on 27/Feb/17

$${(x+y)}^n=\underset{k=0}{\sum ^n}\left(\begin{array}{c}n\\ k\end{array}\right)x^k{y}^{n-k}$$$${(x-y)}^n=???????$$

Answered by mrW1 last updated on 27/Feb/17

$${(x-y)}^n=\underset{k=0}{\sum ^n}\left(\begin{array}{c}n\\ k\end{array}\right){(-1)}^{n-k}{x}^k{y}^{n-k}$$

Commented by geovane10math last updated on 27/Feb/17

$$\mathrm{Thanks}!$$

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