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Question Number 108593 by Rasikh last updated on 18/Aug/20

Answered by Her_Majesty last updated on 18/Aug/20

$${(-1)}^x=e^{xln(-1)}=e^{i\pi x}=cos\pi x+isin\pi x$$$$\Rightarrow \int {(-1)}^{x}dx=\frac{1}{\pi }(sin\pi x-icos\pi x)+C$$

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