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Question Number 108626 by I want to learn more last updated on 18/Aug/20

Answered by Aziztisffola last updated on 18/Aug/20

$${\mathrm{A}}_{\frac{1}{2}\mathrm{circle}}=\frac{1}{2}\pi {\left(\frac{\mathrm{a}}{2}\right)}^2=\frac{\pi {\mathrm{a}}^2}{8}$$$${\mathrm{A}}_{\mathrm{rectangle}}={2\mathrm{a}}^2$$$${\mathrm{A}}_{\mathrm{triangle}}=\frac{\mathrm{A}}{2}$$$${\mathrm{A}}_{2\mathrm{square}}=2\mathrm{A}$$$${\mathrm{A}}_{\mathrm{grey}}=\frac{\pi {\mathrm{a}}^2}{8}+{2\mathrm{a}}^2+\frac{\mathrm{A}}{2}+2\mathrm{A}-\mathrm{A}$$$$=\left(\frac{16+\pi }{8}\right){\mathrm{a}}^2+\frac{3\mathrm{A}}{2}$$$$\mathrm{with}\mathrm{A}=\frac{{\mathrm{a}}^2}{2}$$$${\mathrm{A}}_{\mathrm{grey}}=\left(\frac{16+\pi }{8}\right){\mathrm{a}}^2+\frac{{3\mathrm{a}}^2}{4}$$$$=\left(\frac{22+\pi }{8}\right){\mathrm{a}}^2$$

Commented by I want to learn more last updated on 18/Aug/20

$$\mathrm{Thanks}\mathrm{sir},\mathrm{i}\mathrm{really}\mathrm{appreciate}.$$

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