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Question Number 108990 by shahria14 last updated on 20/Aug/20
Answered by bobhans last updated on 20/Aug/20
♭o♭hansς−−−−ςsetx−1=♭→{x=5→♭=4x=1→♭=0;dx=d♭∫51f(x−1)dx=∫40f(♭)d♭=0
Answered by Aziztisffola last updated on 20/Aug/20
t=x−1⇒dt=dx∫15f(x−1)dx=∫04f(t)dt=0
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