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Question Number 109047 by Eric002 last updated on 20/Aug/20

∫_(−2) ^∞ (x+2)^5 e^(−(x+2)) dx  ∫_0 ^1 ((tan(x))/x)dx

$$\int_{−\mathrm{2}} ^{\infty} \left({x}+\mathrm{2}\right)^{\mathrm{5}} {e}^{−\left({x}+\mathrm{2}\right)} {dx} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{tan}\left({x}\right)}{{x}}{dx} \\ $$

Answered by Dwaipayan Shikari last updated on 20/Aug/20

∫_0 ^∞ t^5 e^(−t) dt       (x+2)=t  =Γ(6)=120

$$\int_{\mathrm{0}} ^{\infty} {t}^{\mathrm{5}} {e}^{−{t}} {dt}\:\:\:\:\:\:\:\left({x}+\mathrm{2}\right)={t} \\ $$$$=\Gamma\left(\mathrm{6}\right)=\mathrm{120} \\ $$

Commented by Eric002 last updated on 20/Aug/20

thank you

$${thank}\:{you}\: \\ $$

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