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Question Number 109068 by n0y0n last updated on 20/Aug/20
Answered by Dwaipayan Shikari last updated on 20/Aug/20
limx→0(cos5x2)1x4=(1−25x42)−2x4.25.(−252)=e−252
limx→0(cos5x2)1x4=y1x4log(cos5x2)=logy1x4log(1+cos5x2−1)=logycos5x2−1x4.log(1+cos5x2−1)cos5x2−1=logy−2sin25x22x4=logy−252=logyy=e−252
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