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Question Number 109068 by n0y0n last updated on 20/Aug/20

Answered by Dwaipayan Shikari last updated on 20/Aug/20

lim_(x→0) (cos5x^2 )^(1/x^4 ) =(1−((25x^4 )/2))^(((−2)/(x^4 .25)).(((−25)/2))) =e^(−((25)/2))

limx0(cos5x2)1x4=(125x42)2x4.25.(252)=e252

Answered by Dwaipayan Shikari last updated on 20/Aug/20

lim_(x→0) (cos5x^2 )^(1/x^4 ) =y  (1/x^4 )log(cos5x^2 )=logy  (1/x^4 )log(1+cos5x^2 −1)=logy  ((cos5x^2 −1)/x^4 ).((log(1+cos5x^2 −1))/(cos5x^2 −1))=logy  ((−2sin^2 ((5x^2 )/2))/x^4 )=logy  −((25)/2)=logy  y=e^(−((25)/2))

limx0(cos5x2)1x4=y1x4log(cos5x2)=logy1x4log(1+cos5x21)=logycos5x21x4.log(1+cos5x21)cos5x21=logy2sin25x22x4=logy252=logyy=e252

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