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Question Number 109201 by aurpeyz last updated on 21/Aug/20

Commented by aurpeyz last updated on 21/Aug/20

$$plshelp$$

Answered by Dwaipayan Shikari last updated on 22/Aug/20

$$Accelaration=\frac{F}{M_{sys}}=\frac{6}{13}\frac{m}{s^2}$$$$T_1=F-ma=6-6.\frac{6}{13}=3.2N$$$$T_2=T_1-m_{0}a=3.2-4.\frac{6}{13}=1.36N$$

Commented by aurpeyz last updated on 02/Sep/20

$$isline3notsupposedtobe{\mathrm{T}}_2={\mathrm{T}}_1-m_{2}a??$$

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