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Question Number 109303 by peter frank last updated on 22/Aug/20

Commented by som(math1967) last updated on 23/Aug/20

$$\mathrm{Acute}\mathrm{angle}\mathrm{between}\mathrm{y}=\mathrm{x}+1$$$$\mathrm{and}\mathrm{x}-\mathrm{axis}{\mathrm{istan}}^{-1}1=\frac{\pi }{4}$$$$\therefore \mathrm{angle}\mathrm{between}\mathrm{bisector}$$$$\mathrm{and}\mathrm{x}-\mathrm{axis}=\frac{\pi }{8}$$$$\therefore \mathrm{gradiant}\mathrm{of}\mathrm{angle}\mathrm{bisector}$$$$=\tan \frac{\pi }{8}=\sqrt{2}-1$$

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