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Question Number 109400 by mohammad17 last updated on 23/Aug/20

Commented by mohammad17 last updated on 23/Aug/20

$h e l p m e s i r ?$
Commented by bobhans last updated on 23/Aug/20

$u s i n g E x a c t d i f f e q u a t i o n$
Commented by mohammad17 last updated on 23/Aug/20

$s i r t h e e q u a t i o n i s n o t e x a c t ?$ $a r e y o u c a n h e l p m e ?$
Commented by mohammad17 last updated on 23/Aug/20

$n o o n e h e r e c a n y o u s o l v e t h i s ?$
	Answered by ajfour last updated on 24/Aug/20

	$(1 + x^{2} y) d x + (x^{2} + 1) y d y = 0$ $\frac{d y}{d x} = - \frac{1}{y} (\frac{1 + x^{2} y}{1 + x^{2}})$ $. . . . . . .$
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