Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 109400 by mohammad17 last updated on 23/Aug/20

Commented by mohammad17 last updated on 23/Aug/20

help me sir?

$${help}\:{me}\:{sir}? \\ $$

Commented by bobhans last updated on 23/Aug/20

using Exact diff equation

$${using}\:{Exact}\:{diff}\:{equation} \\ $$

Commented by mohammad17 last updated on 23/Aug/20

sir the equation is not exact ?  are you can help me ?

$${sir}\:{the}\:{equation}\:{is}\:{not}\:{exact}\:? \\ $$$${are}\:{you}\:{can}\:{help}\:{me}\:? \\ $$

Commented by mohammad17 last updated on 23/Aug/20

no one here can you solve this ?

$${no}\:{one}\:{here}\:{can}\:{you}\:{solve}\:{this}\:? \\ $$

Answered by ajfour last updated on 24/Aug/20

(1+x^2 y)dx+(x^2 +1)ydy=0  (dy/dx)=−(1/y)(((1+x^2 y)/(1+x^2 )))  .......

$$\left(\mathrm{1}+{x}^{\mathrm{2}} {y}\right){dx}+\left({x}^{\mathrm{2}} +\mathrm{1}\right){ydy}=\mathrm{0} \\ $$$$\frac{{dy}}{{dx}}=−\frac{\mathrm{1}}{{y}}\left(\frac{\mathrm{1}+{x}^{\mathrm{2}} {y}}{\mathrm{1}+{x}^{\mathrm{2}} }\right) \\ $$$$....... \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com