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Question Number 109497 by rinasitorus_ last updated on 24/Aug/20

Answered by nurmaya_silaban last updated on 24/Aug/20

$$1)a.\frac{1}{3}+\frac{3}{5}=\frac{5}{15}+\frac{9}{15}=\frac{14}{15}$$$$\mathrm{b}.\frac{1}{3}\times \frac{3}{5}=\frac{3}{15}$$$$\mathrm{c}.\frac{2}{3}-\frac{3}{7}=\frac{14}{21}-\frac{9}{21}=\frac{5}{21}$$$$\mathrm{d}.\frac{2}{3}:\frac{3}{7}=\frac{2}{3}\times \frac{7}{3}=\frac{14}{9}$$$$$$$$2)a.3\mathrm{x}+\frac{2}{7}=1\frac{1}{3}$$$$3\mathrm{x}+\frac{2}{7}=\frac{4}{3}$$$$3\mathrm{x}=\frac{4}{3}-\frac{2}{7}$$$$3\mathrm{x}=\frac{28}{21}-\frac{6}{21}$$$$3\mathrm{x}=\frac{22}{21}$$$$\mathrm{x}=\frac{66}{21}$$$$\mathrm{b}.3+\frac{2}{\mathrm{x}}=1\frac{1}{3}$$$$3+\frac{2}{\mathrm{x}}=\frac{4}{3}$$$$\frac{3}{1}-\frac{4}{3}=\frac{-2}{\mathrm{x}}$$$$\frac{9}{3}-\frac{4}{3}=\frac{-2}{\mathrm{x}}$$$$\frac{5}{3}=\frac{-2}{\mathrm{x}}$$$$5\mathrm{x}=-6$$$$\mathrm{x}=\frac{-6}{5}$$$$c.\frac{2}{3}\mathrm{x}-\frac{2}{7}=1\frac{1}{3}$$$$\frac{2}{3}\mathrm{x}-\frac{2}{7}=\frac{4}{3}$$$$\frac{2}{3}\mathrm{x}=\frac{4}{3}+\frac{2}{7}$$$$\frac{2}{3}\mathrm{x}=\frac{28}{21}+\frac{6}{21}$$$$\frac{2}{3}\mathrm{x}=\frac{34}{21}$$$$42\mathrm{x}=102$$$$\mathrm{x}=\frac{102}{42}$$$$d.3+\frac{x}{2}=1\frac{1}{3}$$$$3+\frac{x}{2}=\frac{4}{3}$$$$\frac{3}{1}-\frac{4}{3}=\frac{-\mathrm{x}}{2}$$$$\frac{9}{3}-\frac{4}{3}=\frac{-\mathrm{x}}{2}$$$$\frac{5}{3}=\frac{-\mathrm{x}}{2}$$$$-3\mathrm{x}=10$$$$\mathrm{x}=-\frac{10}{3}$$$$$$$$$$$$$$$$$$$$$$

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