((sin 2𝛂+2sin 𝛂∙cos 2𝛂)/(1+cos 𝛂+cos2 𝛂+cos3 𝛂))


Question and Answers Forum

All Questions Topic List
Algebra Questions
Previous in All Question Next in All Question
Previous in Algebra Next in Algebra
Question Number 109625 by qwerty111 last updated on 24/Aug/20

$\frac{\sin 2 α + 2 \sin α \cdot \cos 2 α}{1 + \cos α + \cos 2 α + \cos 3 α}$
Commented by nimnim last updated on 24/Aug/20

$t a n α$
Commented by kaivan.ahmadi last updated on 24/Aug/20

$\frac{2 s i n α c o s α + 2 s i n α (2 {c o s}^{2} α - 1)}{1 + c o s α + (2 {c o s}^{2} α - 1) + (4 {c o s}^{3} α - 3 c o s α)} =$ $\frac{2 s i n α (2 {c o s}^{2} α + c o s α - 1)}{4 {c o s}^{3} α + 2 {c o s}^{2} α - 2 c o s α} = \frac{2 s i n α (2 {c o s}^{2} α + c o s α - 1)}{2 c o s α (2 {c o s}^{2} α + c o s α - 1)} = \frac{s i n α}{c o s α}$ $t g α$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum