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Question Number 109640 by hhryhrry2 last updated on 24/Aug/20

Commented by kaivan.ahmadi last updated on 24/Aug/20

$$a.$$$$\underset{2}{\sum ^6}(g^2+2g)-\underset{2}{\sum ^6}(3(g+3)-5)=\underset{2}{\sum ^6}(g^2-g-4)=$$$$\underset{3}{\sum ^7}({(g-1)}^2-(g-1)-4)=\underset{3}{\sum ^7}(g^2-3g-4)=$$$$\underset{3}{\sum ^7}(g-4)(g+1)$$

Commented by kaivan.ahmadi last updated on 24/Aug/20

$$b.$$$$\underset{5}{\sum ^9}{(2b-5)}^2=\underset{1}{\sum ^5}{(2(b+4)-5)}^2=\underset{1}{\sum ^5}{(2b-3)}^2=$$$$\underset{1}{\sum ^5}(4b^2-12b+9)=4\underset{1}{\sum ^5}{b}^2-3\underset{1}{\sum ^5}(4b-3)$$$$$$

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