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Question Number 109642 by malwan last updated on 24/Aug/20

Answered by Dwaipayan Shikari last updated on 24/Aug/20

$$\int \frac{dx}{\sqrt{2{tan}^2\theta +2}}\frac{\sqrt{2}}{5}{sec}^2\theta d\theta x=\frac{\sqrt{2}}{5}tan\theta$$$$\frac{1}{5}\int sec\theta d\theta$$$$\frac{1}{5}log(sec\theta +tan\theta )=\frac{1}{5}log(\sqrt{\frac{25x^2+1}{2}}+\frac{5x}{\sqrt{2}})+C$$

Commented by malwan last updated on 24/Aug/20

$$greatSir$$$$thankyousomuch$$

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