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Question Number 109699 by bemath last updated on 25/Aug/20

     x(x−1)^2  ≥ 12(x−1)

x(x1)212(x1)

Answered by bemath last updated on 25/Aug/20

⇔ (x−1)(x(x−1)−12)≥0  ⇔(x−1)(x−4)(x+3)≥0  ⇔ −3≤x≤1 ∪ x≥4

(x1)(x(x1)12)0(x1)(x4)(x+3)03x1x4

Commented by nimnim last updated on 25/Aug/20

Nice..

Nice..

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