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Question Number 109754 by joki last updated on 25/Aug/20
1.specifyvalueabsolutexif?b.∣2x+3∣+x−3=0
Answered by Her_Majesty last updated on 25/Aug/20
∣3x+1x−2∣=1(1)x<−1/33x+1x−2=1⇔x=−3/2(2)−1/3⩽x<2−3x+1x−2=1⇔x=1/4(3)2<xnosolution⇒x=−3/2∨x=1/4∣2x+3∣+x−3=0(1)x<−3/2−(2x+3)+x−3=0⇔x=−6(2)x⩾−3/22x+3+x−3=0⇔x=0⇒x=−6∨x=0
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