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Question Number 109769 by Karani last updated on 25/Aug/20
limx→Π1−cosxcos2xcos3x1−cosx=?
Answered by bemath last updated on 25/Aug/20
△♭ϵmath▽limx→π1−cosπ.cos2π.cos3π1−cosπ=1−(−1)(1)(−1)2=0
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