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Question Number 109888 by bagusadisaputra last updated on 26/Aug/20

$$2^{x+5}=\sqrt{8^x}$$

Answered by som(math1967) last updated on 26/Aug/20

$$2^{\mathrm{x}+5}={\left(2^{3\mathrm{x}}\right)}^{\frac{1}{2}}$$$$2^{\mathrm{x}+5}=2^{\frac{3\mathrm{x}}{2}}$$$$\mathrm{x}+5=\frac{3\mathrm{x}}{2}$$$$2\mathrm{x}+10=3\mathrm{x}$$$$\therefore \mathrm{x}=10\mathrm{ans}$$

Answered by Rasheed.Sindhi last updated on 26/Aug/20

$$\mathrm{AnOther}\mathrm{way}\circlearrowleft$$$$2^{x+5}=\sqrt{8^x}$$$$2=8^{1/3}$$$$8^{\frac{x+5}{3}}=8^{\frac{x}{2}}$$$$\frac{x+5}{3}=\frac{x}{2}$$$$2x+10=3x$$$$x=10$$

Answered by Dwaipayan Shikari last updated on 26/Aug/20

$$(x+5)log\left(2\right)=\frac{3x}{2}log2$$$$x=10$$

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