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Question Number 110722 by ZiYangLee last updated on 30/Aug/20

Answered by ajfour last updated on 30/Aug/20

(a−b)x+(b−a)=0 ⇒ x=1 ⇒ a+b=−1 .

(a−b)x+(b−a)=0⇒x=1⇒a+b=−1.

Answered by bobhans last updated on 30/Aug/20

⇔ x^2 = x^2 ⇔ −b−ax = −bx−a ⇔ (b−a)x = b−a ; b ≠ a ⇔ x = 1 ⇒1^2 +a+b = 0; a+b = −1

⇔x2=x2⇔−b−ax=−bx−a⇔(b−a)x=b−a;b≠a⇔x=1⇒12+a+b=0;a+b=−1

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