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Question Number 110736 by abdullahquwatan last updated on 30/Aug/20

$$\mathrm{given}f\left(x\right)={ax}^2+bx+c\mathrm{and}f\left(x\right)$$ $$\mathrm{is}\mathrm{negative}\mathrm{on}a<x<b.\mathrm{The}\mathrm{value}\mathrm{of}$$ $$\underset{x\to a}{\lim }\frac{{(x-a)}^2}{1-\cos \left(f\left(x\right)\right)}$$

Commented byabdullahquwatan last updated on 30/Aug/20

$$\mathrm{answer}\mathrm{in}a\mathrm{and}b$$

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