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Question Number 110845 by bemath last updated on 31/Aug/20

$${({\mathrm{x}}^2+3\mathrm{x}-10)}^{{\mathrm{x}}^3-9\mathrm{x}}={({\mathrm{x}}^2+3\mathrm{x}-10)}^{{3\mathrm{x}}^2-8\mathrm{x}}$$

Answered by john santu last updated on 31/Aug/20

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