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Question Number 110860 by I want to learn more last updated on 31/Aug/20

Answered by mr W last updated on 31/Aug/20

Commented by mr W last updated on 31/Aug/20

$$F_B\cos 60°=Mg$$$$\Rightarrow F_B=\frac{Mg}{\cos 60°}$$$$F_A=F_B\sin 60°=Mg\tan 60°$$

Commented by I want to learn more last updated on 31/Aug/20

$$\mathrm{Thanks}\mathrm{sir},\mathrm{i}\mathrm{appreciate}.$$$$\mathrm{Should}\mathrm{i}\mathrm{put}\mathrm{Mg}=500\mathrm{N}???$$$$\mathrm{And}\mathrm{are}\mathrm{we}\mathrm{not}\mathrm{using}\mathrm{the}\mathrm{radius}\mathrm{sir}?$$

Commented by mr W last updated on 31/Aug/20

$$yes$$

Commented by I want to learn more last updated on 31/Aug/20

$$\mathrm{Thanks}\mathrm{sir}$$

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