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Question Number 111183 by mohannalamati last updated on 02/Sep/20

y^(old)

$${y}^{{old}} \\ $$

Commented by bemath last updated on 02/Sep/20

what your question ?

$$\mathrm{what}\:\mathrm{your}\:\mathrm{question}\:? \\ $$

Answered by mathmax by abdo last updated on 02/Sep/20

∼ y^(young)

$$\sim\:\mathrm{y}^{\mathrm{young}} \\ $$

Answered by bobhans last updated on 03/Sep/20

⇔ y^(afdoll.(√(great)))

$$\Leftrightarrow\:\mathrm{y}^{\mathrm{afdoll}.\sqrt{\mathrm{great}}} \\ $$

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