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Question Number 111272 by Aina Samuel Temidayo last updated on 03/Sep/20

$$\mathrm{Tricolours}\mathrm{flags}(\mathrm{each}\mathrm{flag}\mathrm{having}$$$$\mathrm{three}\mathrm{different}\mathrm{strips}\mathrm{of}$$$$\mathrm{non}-\mathrm{overlapping}\mathrm{colours})\mathrm{are}\mathrm{to}\mathrm{be}$$$$\mathrm{designed}\mathrm{using}\mathrm{white},\mathrm{blue},\mathrm{red},\mathrm{yellow}$$$$\mathrm{and}\mathrm{black}\mathrm{strips}.\mathrm{How}\mathrm{many}\mathrm{of}\mathrm{the}$$$$\mathrm{flags}\mathrm{have}\mathrm{blue}\mathrm{colour}?$$

Answered by 1549442205PVT last updated on 03/Sep/20

$$\mathrm{Number}\mathrm{of}\mathrm{the}\mathrm{flags}\mathrm{have}\mathrm{blue}\mathrm{colour}$$$$\mathrm{equal}\mathrm{to}{\mathrm{C}}_4^2=\frac{4!}{2!2!}=6$$

Commented by Aina Samuel Temidayo last updated on 03/Sep/20

$$\mathrm{Thanks}.$$

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