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Question Number 111441 by PNL last updated on 03/Sep/20

solve { ((y′′ −2y′+2y=sinht)),((y′(0)=1 , y(0)=1)) :}

$${solve} \\ $$$$ \\ $$$$\begin{cases}{{y}''\:−\mathrm{2}{y}'+\mathrm{2}{y}={sinht}}\\{{y}'\left(\mathrm{0}\right)=\mathrm{1}\:,\:{y}\left(\mathrm{0}\right)=\mathrm{1}}\end{cases} \\ $$

Answered by Aziztisffola last updated on 03/Sep/20

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