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Question Number 111583 by Rio Michael last updated on 04/Sep/20

$$\mathrm{without}\mathrm{using}\mathrm{a}\mathrm{substitution}\mathrm{for}{3}^x\mathrm{solve}\mathrm{the}\mathrm{equation}$$$$9^x-3^{x+2}-36=0$$

Answered by bemath last updated on 04/Sep/20

$$9^x-9.3^x-36=0$$$$3^x=\frac{9+\sqrt{81+144}}{2}=\frac{9+15}{2}=12$$$$x=\log {}_3\left(12\right)=1+2\log {}_3\left(2\right)$$

Commented by Rio Michael last updated on 04/Sep/20

$$\mathrm{thanks},\mathrm{but}\mathrm{anyother}\mathrm{method}\mathrm{sir}?$$

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