Question and Answers Forum

All Questions      Topic List

Differentiation Questions

Previous in All Question      Next in All Question      

Previous in Differentiation      Next in Differentiation      

Question Number 111584 by ajfour last updated on 04/Sep/20

Answered by ajfour last updated on 04/Sep/20

$$C(0,y);A(x,0);B(z,z^2)$$$$\sqrt{{(x-z)}^2+z^4}+\sqrt{z^2+{(y-z^2)}^2}=a$$$$△=z^3+\frac{1}{2}z(y-z^2)+\frac{1}{2}(x-z)z^2$$$$letx-z=z^2\tan \theta$$$$\mathrm{\&}y-z^2=z\tan \varphi$$$$\Rightarrow z^2\sec \theta +z\sec \varphi =a$$$$\mathrm{\&}△=z^3+\frac{z^2}{2}\tan \varphi +\frac{z^4}{2}\tan \theta$$$$someonepleasehelp..$$

Commented by mr W last updated on 05/Sep/20

$$P=z^3+\frac{z^2}{2}\tan \varphi +\frac{z^4}{2}\tan \theta +\lambda (z^2\sec \theta +z\sec \varphi -a)$$$$\frac{\partial P}{\partial z}=0,\frac{\partial P}{\partial \theta }=0,\frac{\partial P}{\partial \varphi }=0,\frac{\partial P}{\partial \lambda }=0$$$$....hardtosolve...$$

Answered by ajfour last updated on 06/Sep/20

Terms of Service

Privacy Policy

Contact: info@tinkutara.com