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Question Number 111937 by bemath last updated on 05/Sep/20

Answered by bobhans last updated on 05/Sep/20

$$\mathrm{let}\mathrm{the}\mathrm{first}\mathrm{five}\mathrm{question}\mathrm{is}\mathrm{number}:$$$$1;2;3;4;5$$$$\mathrm{case}\left(1\right)\Rightarrow \mathrm{C}{}_4^5\times \mathrm{C}{}_4^5=25$$$$\mathrm{case}\left(2\right)\Rightarrow \mathrm{C}{}_5^5\times \mathrm{C}{}_3^5=1\times 10=10$$$$\mathrm{totally}25+10=35.$$

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