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Question Number 112163 by bobhans last updated on 06/Sep/20

$$\mathrm{In}\mathrm{a}\mathrm{class}\mathrm{of}30\mathrm{pupils},12\mathrm{are}\mathrm{girls}\mathrm{and}$$$$2\mathrm{of}\mathrm{them}\mathrm{are}\mathrm{short}-\mathrm{sighted}.\mathrm{Among}$$$$18\mathrm{boys},6\mathrm{are}\mathrm{short}-\mathrm{sighted}.\mathrm{If}\mathrm{a}\mathrm{pupil}$$$$\mathrm{is}\mathrm{selected}\mathrm{at}\mathrm{random},\mathrm{what}\mathrm{is}\mathrm{the}\mathrm{probability}$$$$\mathrm{that}\mathrm{the}\mathrm{pupil}\mathrm{chosen}\mathrm{will}\mathrm{be}$$$$\{\begin{array}{l}\left(\mathrm{a}\right)\mathrm{a}\mathrm{girls}\\ \left(\mathrm{b}\right)\mathrm{short}-\mathrm{sighted}\\ \left(\mathrm{c}\right)\mathrm{a}\mathrm{short}-\mathrm{sighted}\mathrm{boy}\end{array}$$

Answered by MJS_new last updated on 06/Sep/20

$$\left(a\right)\frac{12}{30}=\frac{2}{5}$$$$\left(b\right)\frac{8}{30}=\frac{4}{15}$$$$\left(c\right)\frac{6}{30}=\frac{1}{5}$$

Commented by bobhans last updated on 06/Sep/20

$$\mathrm{hihihi}....\mathrm{thank}\mathrm{you}$$

Commented by MJS_new last updated on 06/Sep/20

...after this hard job I need a break ��

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