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Question Number 112370 by Eric002 last updated on 07/Sep/20

$$\underset{x\to 0^{+}}{\lim }\frac{x-\lfloor x\rfloor }{x^2}$$$$\lfloor x\rfloor isfloorfunction$$

Commented by kaivan.ahmadi last updated on 07/Sep/20

$$\lfloor 0^{+}\rfloor =0$$$$\Rightarrow {lim}_{x{\to }^{+}}\frac{x}{x^2}={lim}_{x\to 0^{+}}\frac{1}{x}=+\mathrm{\infty }$$$$$$

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