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Question Number 112572 by Aina Samuel Temidayo last updated on 08/Sep/20
Commented by mr W last updated on 08/Sep/20
seeQ112533
Answered by mr W last updated on 09/Sep/20
1&11...}10pairs10&2021&31...}10pairs30&40......81&91...}10pairs90&100i.e.wecanselectatmost50numberswithouttwonumbersamongthemwhosedifferenceis10.⇒theansweris51.
Commented by Aina Samuel Temidayo last updated on 09/Sep/20
Thanks.
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