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Question Number 128285 by john_santu last updated on 06/Jan/21
cos(π7)−cos(2π7)+cos(3π7)=?
Answered by liberty last updated on 06/Jan/21
letφ=cos(π7)−cos(2π7)+cos(3π7)φ=cos(π7)+cos(3π7)+cos(5π7)⇒2φsint=2sintcost+2sintcos3t+2sintcos5twheret=π7⇒2φsint=sin2t+sin4t−sin2t+sin6t−sin4t⇒2φsint=sin6t⇒φ=sin(6π7)2sin(π7)=12
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