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Question Number 112818 by Algoritm last updated on 09/Sep/20

Commented by Algoritm last updated on 09/Sep/20

$${\mathrm{xlog}}_2{2}^{{\mathrm{x}}^{\mathrm{x}}}=3\ne 2^{{\mathrm{x}}^{{\mathrm{x}}^{\mathrm{x}}}}=8$$

Commented by Algoritm last updated on 09/Sep/20

$${\mathrm{x}}^{{\mathrm{x}}^{\mathrm{x}}}=3$$

Commented by mr W last updated on 09/Sep/20

$$ithink{it}^{\prime }snotcorrectsir!$$$$2^{x^{x^x}}\ne {\left(2^{x^x}\right)}^x=2^{x^{x}x}=2^{x^{x+1}}$$$$2^{x^x}\ne {\left(2^x\right)}^x=2^{x^2}$$

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