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Question Number 1130 by 123456 last updated on 22/Jun/15
f:R→Rf(xy)+f(x+y)=f(x)f(y)+f(x)+f(y)f(−1)=?f(0)=?f(+1)=?
Answered by prakash jain last updated on 23/Jun/15
f(x)=xf(x+y)+f(xy)=x+y+xy=f(x)+f(y)+f(x)f(y)f(0)=0f(1)=1f(−1)=−1
Commented by Rasheed Soomro last updated on 15/Jul/15
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