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Question Number 11301 by tawa last updated on 19/Mar/17

ABCD is a cyclic quad and the diagonal AC and BD intersect at H.   △DAC = 41° and △AHB = 70°. calulate  △ACB

$$\mathrm{ABCD}\:\mathrm{is}\:\mathrm{a}\:\mathrm{cyclic}\:\mathrm{quad}\:\mathrm{and}\:\mathrm{the}\:\mathrm{diagonal}\:\mathrm{AC}\:\mathrm{and}\:\mathrm{BD}\:\mathrm{intersect}\:\mathrm{at}\:\mathrm{H}.\: \\ $$$$\bigtriangleup\mathrm{DAC}\:=\:\mathrm{41}°\:\mathrm{and}\:\bigtriangleup\mathrm{AHB}\:=\:\mathrm{70}°.\:\mathrm{calulate}\:\:\bigtriangleup\mathrm{ACB} \\ $$

Commented by sandy_suhendra last updated on 20/Mar/17

do you mean ∠DAC, ∠AHB and ∠ACB?

$$\mathrm{do}\:\mathrm{you}\:\mathrm{mean}\:\angle\mathrm{DAC},\:\angle\mathrm{AHB}\:\mathrm{and}\:\angle\mathrm{ACB}? \\ $$

Answered by sandy_suhendra last updated on 20/Mar/17

Commented by tawa last updated on 20/Mar/17

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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