Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 113154 by I want to learn more last updated on 11/Sep/20

$$\mathrm{If}\lfloor \mathrm{x}+\sqrt{5}\rfloor =\lfloor \mathrm{x}\rfloor +\lfloor 5\rfloor$$$$\mathrm{then}\lfloor \mathrm{x}\rfloor -\mathrm{x}\mathrm{would}\mathrm{be}\mathrm{greater}\mathrm{than}$$$$\left(\mathrm{a}\right)\sqrt{5}-2\left(\mathrm{b}\right)\sqrt{5}-3\left(\mathrm{c}\right)\sqrt{5}\left(\mathrm{d}\right)\sqrt{5}+1\left(\mathrm{e}\right)\sqrt{5}-1$$

Answered by 1549442205PVT last updated on 11/Sep/20

$$\left[\mathrm{x}\right]-\mathrm{x}<0,\sqrt{5}-2>0,\sqrt{5}>0,\sqrt{5}+1>0,\sqrt{5}-1>0$$$$\sqrt{5}-3<0,\mathrm{so}\left[\mathrm{x}\right]-\mathrm{x}>\sqrt{5}-3$$$$\mathbf{Choose}\mathbf{b})$$

Commented by I want to learn more last updated on 11/Sep/20

$$\mathrm{Thanks}\mathrm{sir}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com