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Question Number 113271 by mathdave last updated on 12/Sep/20

solve the initial boundary value  problem of wave equation  ((∂^2 u(x,t))/∂t^2 )=9((∂^2 u(x,t))/∂x^2 ),0<x<2,t>0  u(0,t)=1,u(2,t)=3,t>0  u(x,0)=2,0<x<2  (∂u/∂t)(x,0)=sin2x,0<x<2

$${solve}\:{the}\:{initial}\:{boundary}\:{value} \\ $$ $${problem}\:{of}\:{wave}\:{equation} \\ $$ $$\frac{\partial^{\mathrm{2}} {u}\left({x},{t}\right)}{\partial{t}^{\mathrm{2}} }=\mathrm{9}\frac{\partial^{\mathrm{2}} {u}\left({x},{t}\right)}{\partial{x}^{\mathrm{2}} },\mathrm{0}<{x}<\mathrm{2},{t}>\mathrm{0} \\ $$ $${u}\left(\mathrm{0},{t}\right)=\mathrm{1},{u}\left(\mathrm{2},{t}\right)=\mathrm{3},{t}>\mathrm{0} \\ $$ $${u}\left({x},\mathrm{0}\right)=\mathrm{2},\mathrm{0}<{x}<\mathrm{2} \\ $$ $$\frac{\partial{u}}{\partial{t}}\left({x},\mathrm{0}\right)=\mathrm{sin2}{x},\mathrm{0}<{x}<\mathrm{2} \\ $$

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