find the angle between x+3(√(3y))=2,(√(3x))−5y=2 help me sir please


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Question Number 113343 by mohammad17 last updated on 12/Sep/20

$f i n d t h e a n g l e b e t w e e n x + 3 \sqrt{3 y} = 2, \sqrt{3 x} - 5 y = 2$ $h e l p m e s i r p l e a s e$
Commented by mr W last updated on 12/Sep/20

$y o u h a v e a s k e d (a l m o s t t h e s a m e)$ $q u e s t i o n s e v e r a l t i m e s, e . g . Q 112902,$ $t h e y a r e a l l a n s w e r e d i n d e t a i l .$
	Answered by Dwaipayan Shikari last updated on 12/Sep/20

	$x + 3 \sqrt{3} y = 2$ $y = - \frac{x}{3 \sqrt{3}} + 2$ $y = \frac{\sqrt{3}}{5} x - 2$ $t a n θ =∣ \frac{\frac{\sqrt{3}}{5} + \frac{1}{3 \sqrt{3}}}{1 - \frac{1}{15}} ∣=∣ \frac{\frac{14}{15 \sqrt{3}}}{\frac{14}{15}} ∣= \frac{1}{\sqrt{3}}$ $θ = \frac{π}{6}$
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