Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 113488 by weltr last updated on 13/Sep/20

$$provethat$$$$\frac{sin\left(2a\right)cos\left(2a\right)}{cos\left(4a\right)}=\frac{1}{2}tan\left(4a\right)$$

Answered by som(math1967) last updated on 13/Sep/20

$$\mathrm{L}.\mathrm{H}.\mathrm{S}=\frac{2\sin 2\alpha \cos 2\alpha }{2\cos 4\alpha }$$$$=\frac{1}{2}\times \frac{\sin 4\alpha }{\cos 4\alpha }=\frac{1}{2}\tan 4\alpha =\mathrm{R}.\mathrm{H}.\mathrm{S}$$

Commented by weltr last updated on 13/Sep/20

$$thanks$$

Answered by floor(10²Eta[1]) last updated on 13/Sep/20

$$\frac{\sin \left(2\mathrm{a}\right)\cos \left(2\mathrm{a}\right)}{\cos \left(4\mathrm{a}\right)}=\frac{2\sin \left(2\mathrm{a}\right)\cos \left(2\mathrm{a}\right)}{2\cos \left(4\mathrm{a}\right)}$$$$=\frac{\sin \left(4\mathrm{a}\right)}{2\cos \left(4\mathrm{a}\right)}=\frac{1}{2}\tan \left(4\mathrm{a}\right)$$$$$$

Commented by weltr last updated on 13/Sep/20

$$thanks$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com