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Question Number 113504 by Khalmohmmad last updated on 13/Sep/20

Commented by Khalmohmmad last updated on 13/Sep/20

$$\mathrm{Please}\mathrm{Solve}$$

Commented by kaivan.ahmadi last updated on 13/Sep/20

$$A^2=\left[\begin{array}{c}12\\ 01\end{array}\right]$$$$A^3=\left[\begin{array}{c}13\\ 01\end{array}\right]$$$$⋮$$$$A^{27}=\left[\begin{array}{c}127\\ 01\end{array}\right]\Rightarrow a+b+c+d=29$$

Commented by bobhans last updated on 13/Sep/20

$$\mathrm{A}=\left(\begin{array}{c}1\mathrm{k}\\ 01\end{array}\right)\Rightarrow {\mathrm{A}}^{\mathrm{n}}=\left(\begin{array}{c}1\mathrm{nk}\\ 01\end{array}\right)$$

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