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Question Number 113565 by bemath last updated on 14/Sep/20
Answered by bobhans last updated on 14/Sep/20
∫(5x2+10)(x3+6x)3dx=∫5(x2+2)(x3+6x)3dx=[u=x3+6x⇒du=3x2+6dx]∫5(u)3(13du)=53∫u3du=512(x3+6x)4+c
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