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Question Number 113794 by aurpeyz last updated on 15/Sep/20

$$\mathrm{find}\mathrm{the}\mathrm{largest}\mathrm{coeeficient}\mathrm{in}{(3\mathrm{x}-2)}^3$$

Answered by mr W last updated on 15/Sep/20

$${(3x-2)}^3={\left(3x\right)}^3+3{\left(3x\right)}^2(-2)+3\left(3x\right){(-2)}^2+{(-2)}^3$$$$=27x^3-54x^2+36x-8$$$$max.coef.=36$$$$min.coef.=-54$$

Commented by aurpeyz last updated on 16/Sep/20

$$thanksSir$$

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