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Question Number 113886 by Aina Samuel Temidayo last updated on 16/Sep/20

Answered by MJS_new last updated on 16/Sep/20

$$\left(a\right)$$

Commented by Aina Samuel Temidayo last updated on 16/Sep/20

$$\mathrm{Solution}\mathrm{please}?$$

Commented by MJS_new last updated on 16/Sep/20

$$\mathrm{lol}...\mathrm{just}\mathrm{use}\mathrm{your}\mathrm{brain}$$

Answered by Rasheed.Sindhi last updated on 16/Sep/20

$$a^x={(x+y+z)}^y,a^y={(x+y+z)}^z,a^z={(x+y+z)}^x$$$$a={(x+y+z)}^{y/x}={(x+y+z)}^{z/y}={(x+y+z)}^{x/z}$$$$\frac{y}{x}=\frac{z}{y}=\frac{x}{z}=\frac{x+y+z}{x+y+z}=1$$$$y=x,z=y,x=z$$$$x=y=z=k\left(say\right)$$$$a^k={(k+k+k)}^k$$$$a=3k$$$$k=a/3=x=y=z$$

Answered by Rasheed.Sindhi last updated on 17/Sep/20

$$Multiplyingallthethree$$$$a^{x+y+z}={(x+y+z)}^{x+y+z}$$$$a=x+y+z...................\mathrm{A}$$$$a^x=a^y,a^y=a^z,a^z=a^x$$$$\frac{a^x}{a^y}=\frac{a^y}{a^z}=\frac{a^z}{a^x}=1$$$$a^{x-y}=a^{y-z}=a^{z-x}=a^0$$$$x-y=y-z=z-x=0$$$$x=y=z=k\left(say\right)$$$$In\mathrm{A}$$$$a=k+k+k=3k\Rightarrow k=a/3$$$$k=x=y=z=a/3$$

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